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in which qv is the ultimate bearing capacity for a vertical concentric load, Nc , Nq , and N are bearing capacity factors, B is the foundation width, q is a uniform surcharge around the foundation, and c and are effective soil cohesion and unity weight, respectively. Note that the N s are functions of the friction angle . For the special case of a footing initially on the surface of a cohesionless soil, c = q = 0, and Equation (18.28) becomes qv = 1 BN . Empirical data summarizing the relationship 2 of this equation (and other theoretical solutions) to empirically observed ultimate bearing capacities are shown in Figure 18.4 (from Ingra and Baecher 1983). Regression analysis on the data yield the predictive relationships, E[N ]L/B=6 = exp{ 1.646 + 0.173 } Var[N ]L/B=6 = (0.0429) exp{ 3.292 + 0.345 }

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Listing 6.7 A disassembly of Cryptex s cluster decryption function. (continued)

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Example: The breeze is dropping, so you move your weight right in and sheet in slightly to head up into more wind. Allow the rudder simply to follow the boat. As you get into more pressure, you sit on the side and the boat comes at and accelerates (the sheet is already in, so no need to sheet). Now bear away to stay in the gust by sheeting out, and the boat will come slightly on top of you. When it is going in its new desired direction sit in slightly so the helm is neutral. The more kicker you apply, the easier it is for the boat to head up. (Think: you often have more kicker on upwind than down.) The closer the course you are sailing is to a reach, the more kicker you need. The least kicker you need is on the run (although you always need some), so the leach returns after opening. (You also need some kicker for tapered masts to support the top of the mast!) If you are making turns downwind and then holding the angle for a bit (going high in the lulls and low in the gusts), it may well be worth playing (constantly adjusting) the kicker.

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Apr 22, 2018 · Decode EAN-128 with ByteScout Barcode Reader SDK https://bytescout.com/​articles ...Duration: 0:58 Posted: Apr 22, 2018

(18.29)

6

00401051 00401055 00401056 00401057 00401058 0040105E 00401060 00401064 00401065 0040106A 0040106F 00401070 00401076 00401078 0040107A 0040107E 00401080 00401088 0040108A 0040108E 0040108F 00401094 00401096 00401098 0040109A 0040109B 004010A1 004010A3 004010A5 004010AB 004010AC 004010B1 004010B7 004010BA 004010BC 004010C2 004010C3 004010C8 004010C9 004010CA 004010CB 004010CC 004010CE 004010CF 004010D0

so, for the case of, say, = 35 , the mean and standard deviation of predicted bearing capacity factor would be, E[N ] = 82 and Var[N ] = 17. Thus, using a rst-order second-moment approximation ( 14) to nd the mean and standard deviation of

LEA EDX,SS:[ESP+18] ; PUSH EDX ; pOffsetHi PUSH EAX ; OffsetLo PUSH ESI ; hFile CALL DS:[<&KERNEL32.SetFilePointer>] PUSH 0 ; pOverlapped = NULL LEA EAX,SS:[ESP+C] ; PUSH EAX ; pBytesRead PUSH 1008 ; BytesToRead = 1008 (4104.) PUSH cryptex.00405050 ; Buffer = cryptex.00405050 PUSH ESI ; hFile CALL DS:[<&KERNEL32.ReadFile>] TEST EAX,EAX JE SHORT cryptex.004010CB MOV EAX,SS:[ESP+18] TEST EAX,EAX MOV DWORD PTR SS:[ESP+14],1008 JE SHORT cryptex.004010C2 LEA ECX,SS:[ESP+14] PUSH ECX PUSH cryptex.00405050 PUSH 0 PUSH 1 PUSH 0 PUSH EAX CALL DS:[<&ADVAPI32.CryptDecrypt>] TEST EAX,EAX JNZ SHORT cryptex.004010C2 CALL DS:[<&KERNEL32.GetLastError>] PUSH EDI ; <%d> PUSH cryptex.004030E8 ; format = ERROR: Unable to decrypt block from cluster %d. CALL DS:[<&MSVCR71.printf>] ADD ESP,8 PUSH 1 ; status = 1 CALL DS:[<&MSVCR71.exit>] POP EDI MOV EAX,cryptex.00405050 POP ESI POP ECX RETN POP EDI XOR EAX,EAX POP ESI POP ECX RETN

Listing 6.7 (continued)

the bearing capacity from Equation (18.28) E[q ] = 1 BE[N ] = 1 (18.5 kN/m3 )(1m)(82) = 760 kPa 2 2

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Jun 9, 2015 · A GS1 Parser for C#. Contribute to ... http://stackoverflow.com/questions/9721718​/ean128-or-gs1-128-decode-c-sharp/28854802#28854802.

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