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In addition to the five standard modifiers, the substitution operator also supports a further two modifiers that modify the way in which substitutions take place A full list of the supported modifiers is given in Table 8-4 The /g operator forces the search and replace operation to take place multiple times, which means that PATTERN is replaced with REPLACEMENT for as many times as PATTERN appears This is done as a one-pass process, however The substitution operation is not put into a loop For example, in the following substitution we replace o with oo :

1 public class BackHanded { 2 int state = 0; 3 BackHanded(int s) { state = s; } 4 public static void main(String hi) { 5 BackHanded b1 = new BackHanded(1); 6 BackHanded b2 = new BackHanded(2); 7 Systemoutprintln(b1go(b1) + " " + b2go(b2)); 8 } 9 int go(BackHanded b) { 10 if(thisstate == 2) { 11 bstate = 5; 12 go(this); 13 } 14 return ++thisstate; 15 } }

$string = 'Both foods'; $string =~ s/o/oo/g;

The result is Booth foooods , not Boooooooooooth foooooooooods ad infinitum However, there are times when such a multiple-pass process is useful In those cases, just place the substitution in a while loop For example, to replace all the double spaces with a single space you might use:

1 while($string =~ s/ / /g);

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G Compilation fails H An exception is thrown at runtime Answer (for Objective 73): F is correct There are only two BackHanded objects The first call to go() is pretty straightforward, but don t get confused; "b" and "this" are referring to the same object The second call to go() is a little trickier the "if" test is true, so go() is invoked a third time The result of the third invocation would be 6, but it s not kept When control is returned to the second invocation of go(), state (from the same object) is incremented again, to 7 A, B, C, D, E, G, and H are incorrect based on the above

Makes the match case insensitive Specifies that if the string has newline or carriage return characters, the ^ and $ operators will now match against a newline boundary, instead of a string boundary Evaluates the expression only once Allows use of to match a newline character Allows you to use white space in the expression for clarity Replaces all occurrences of the found expression with the replacement text Evaluates the replacement as if it were a Perl statement, and uses its return value as the replacement text

Table 8-4

The while loop will drop out as soon as the substitution fails to find a double space The /e modifier causes Perl to evaluate the REPLACEMENT text as if it were a Perl expression, and then to use the value as the replacement string We ve already seen an example of this when converting a date from traditional American slashed format into the Japanese/Universal format:

$c =~ s{(\d+)/(\d+)/(\d+)}{sprintf("%04d%02d%02d",$3,$1,$2)}e;

3 Given:

We have to use sprintf in this case; otherwise, a single-digit day or month would truncate the numeric digits from the eight required for example, 26/3/2000 would become 2000326 instead of 20000326

Translation is similar, but not identical, to the principles of substitution, but unlike substitution, translation (or transliteration) does not use regular expressions for its search on replacement values The translation operators are

The translation replaces all occurrences of the characters in SEARCHLIST with the corresponding characters in REPLACEMENTLIST For example, using the The cat sat on the mat string we have been using in this chapter:

42 43 44 45 46 47 String s = ""; if(011 == 9) s += 4; if(0x11 == 17) s += 5; Integer I = 12345; if(IintValue() == IntegervalueOf("12345")) s += 6; Systemoutprintln(s);

$string =~ tr/a/o/; print "$string\n";

this script prints out The cot sot on the mot Standard Perl ranges can also be used, allowing you to specify ranges of characters either by letter or numerical value To change the case of the string, you might use

$string =~ tr/a-z/A-Z/;

Answer (for Objective 31): E is correct Line 43 is comparing an octal int to an int Line 44 is comparing a hexadecimal int to an int Line 46 is comparing an int to an Integer, which is unboxed before the comparison is made A, B, C, D, F, and G are incorrect based on the above

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